## an elevator descends into a mine shaft at the rate of 6m/min. If the descent starts from 10m above the ground level how long will it take to

Question

an elevator descends into a mine shaft at the rate of 6m/min. If the descent starts from 10m above the ground level how long will it take to reach -350m deep under the ground. please help fast Give clear explanation also

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Math
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2021-10-19T00:19:55+00:00
2021-10-19T00:19:55+00:00 1 Answer
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## Answers ( )

ANSWER ;

3600 seconds

Step-by-step explanation:

total distance the elevator has to cover = 360 metre

velocity = 6m/min = 6/60 m/s = 0.1 m/s

Use the formula t= S/v

t = 360/0.1

t = 3600 seconds = 60 minutes = 1 hour

Hope you are satisfied by my answer

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